The experimental design explains that 2.00 g of Strontium nitrate is dissolved in 50 mL of water and then reacted with excess Copper (II) sulphate (3.00 g). The product would be a precipitate (Strontium sulphate and Copper (II) nitrate) After mixing the solutions the precipitate would be seperated by filtration, dried and then weighed.
The balanced equation for this reaction is :
Sr (NO3)2 + CuSO4 ---> Sr SO4 + Cu(NO3)2
By calculating how many grams of Strontium sulphate should be produced after 2.00 g of Strontium nitrate is completely reacts, we came up with 1.74 g of SrSO4.
What to do? :
- Carefully measure about 3.00 g of Copper (II) sulphate.
- Dissolve the Copper (II) sulphate in 50 mL of water.
- Carefully measure 2.00 g of Strontium nitrate and dissolve it in 50 mL of water.
- Slowly pour the two solutions together.
- Stir the mixture to complete the reaction
- Write your group name on a piece of filter paper
- Find and record the mass of the filter paper
- Using a funnel and an Erlenmeyer flask, place the filter paper in the funnel and slowly pour the mixture into the funnel.
- Pour the filtrate into the waste collection bottle
- Finally, place the filter paper in the drying oven and record the mass when its dry.
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